what is the number of ion in 7.41g of calcium hydoxide Ca(OH)2 ?
number of particles = mole x Avogadro constantAvogadro constant is 6.0 × 1023 mol–1.Mr of Ca(OH)2 is 7.41g mol-1mole = Mass / Mr = 7.41/7.41 = 1 moleThe question is asking: the number of ion = ?So, in this compound, we have 3 ions, which are Ca2+ and 2 OH-. Therefore, we times the mole by 3. We now have 3 moles.The total of ion = mole x Avogadro constant = 3 mole x 6.0 × 1023 mol–1 = 1.8 x 10 24No unit is required in this answer!
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