what is the number of ion in 7.41g of calcium hydoxide Ca(OH)2 ?

number of particles = mole x Avogadro constantAvogadro constant is 6.0 × 10²³ mol^–1.Mr of Ca(OH)₂ is 7.41g mol^-1mole = Mass / Mr = 7.41/7.41 = 1 moleThe question is asking: the number of ion = ?So, in this compound, we have 3 ions, which are Ca²⁺ and 2 OH^-. Therefore, we times the mole by 3. We now have 3 moles.The total of ion = mole x Avogadro constant = 3 mole x 6.0 × 10²³ mol^–1 = 1.8 x 10 ²⁴No unit is required in this answer!