Find a tutor
How it works
Prices
Resources
For schools
Become a tutor
Answers
>
Maths
>
GCSE
>
Article
Solve algebraically the simultaneous equations x^2 +y^2 = 25, y – 3x = 13
Rearrange y - 3x = 13y = 3x + 13 2. Substitute into x^2 +y^2 = 25x^2 + (3x + 13)^2 = 25 3. Expand bracketx^2 +(9x^2 + 39x +39x +169) = 25 4. Form quadratic equation 10x^2 + 78x + 144 = 0 (Dividing by 2 makes factorising easier)5x^2 + 39x + 72 = 0 5. Factorise (5x + 24)(x + 3) = 0 6. Solve for xx = -24/5, x = -3 7. Substitute values of x into y = 3x +13 to find y values x = -24/5, y = -7/5x = -3, y = 4
Answered by Emily N. •
Maths tutor
4173 Views
See similar Maths GCSE tutors
Related Maths GCSE answers
All answers ▸
solve x^2 - 2 < 2
168 is 4/7 of a number. What is the number?
Solve the simultaneous equations: 2x + 3y = 5 and 3x + 4y = 12
You are given that f(x) = cx + d and that f(0) = -6 and f(2) = 10. Find the values of c and d.
We're here to help
Contact us
Message us on Whatsapp
+44 (0) 203 773 6020
Company Information
Careers
Blog
Subject answers
Become a tutor
Schools
Safeguarding policy
FAQs
Using the Online Lesson Space
Testimonials & press
Sitemap
Popular Requests
Maths tutor
Chemistry tutor
Physics tutor
Biology tutor
English tutor
GCSE tutors
A level tutors
IB tutors
Physics & Maths tutors
Chemistry & Maths tutors
GCSE Maths tutors
© MyTutorWeb Ltd 2013–2024
Terms & Conditions
|
Privacy Policy
|
Cookie Preferences
CLICK CEOP
Internet Safety
Payment Security
Cyber
Essentials
Cookie Preferences