Person A, weighing 35 kg, is sitting 10m away from a seesaw pivot. Person B, weighing 50 kg, it sitting at the other end, at a distance d. Calculate d, in order for the seesaw not to topple over. (g=10m/s^2)

Force@A: F_A = m_A x g = 35 x 10 = 350NAnticlockwise moment: M_A = F_A x d_A= 350 x 10 = 3500NmForce @B: F_B=m_b x g = 50 x 10 = 500NClockwise moment: M_c= F_B x d_BFor the seesaw to be in equilibrium, M_A=M_c (1)But M_c= F_Bx d_B (2)(1), (2) => M_A = F_Bx d_B => d_B= M_A/F_B = 3500/500 =7m