Solve algebraically the simultaneous equations: 6x=5-2y 12.5=3x+3y

  1. Rearrange both equations into the form ax + by = c. 3x+3y = 12.5 6x +2y = 5. 2) Make either x or y have the same coefficient in each equation. In this case we use x, to do this we multiply the first equation by two to get 6x. The second equation remains the same. 6x + 6y = 25. 6x + 2y =5. 3) We can now solve for y by subtracting equation 2 from equation 1. 4y = 20. y = 5. 4) Substitute y into the equation to find x. 6x + 10 = 5. x = -5/6. 5) Substitute your answers back into the equation to check they are correct. You may use a calculator.
LW
Answered by Laura W. Maths tutor

2733 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

F(X)= 4/(x-3) g(x)= (x+2)/x solve fg(a)= 1


Why do you need simultaneous equations?


There are n sweets in a bag, 6 of which are orange. If the probablility of eating 2 orange sweets from the bag, one after the other, is 1/3, show that n^2 - n - 90 = 0. State any assumptions made.


Solve for simultaneous equations x +5y =9 and 3x + 2y =5.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences