Solve algebraically the simultaneous equations: 6x=5-2y 12.5=3x+3y

  1. Rearrange both equations into the form ax + by = c. 3x+3y = 12.5 6x +2y = 5. 2) Make either x or y have the same coefficient in each equation. In this case we use x, to do this we multiply the first equation by two to get 6x. The second equation remains the same. 6x + 6y = 25. 6x + 2y =5. 3) We can now solve for y by subtracting equation 2 from equation 1. 4y = 20. y = 5. 4) Substitute y into the equation to find x. 6x + 10 = 5. x = -5/6. 5) Substitute your answers back into the equation to check they are correct. You may use a calculator.
Answered by Laura W. Maths tutor

2614 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand and simplify 3(2x + 5) – 2(x – 4)


A cylindrical beaker has a height of 16 cm and a diameter at its bottom of 10 cm. What is its volume? Give your answer to 2 decimal places.


Show that the following 2 lines are parallel: l1: 3y=15x+17 l2: 7y+5=35x


How do you turn 0.11111... (recurring) into a fraction


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences