A block of mass 5 kg is being pushed over level ground by rod at 60 degrees to horizontal with force 40 N with acc. 1.5 what is the frictional force of the surface and draw a diagram with the forces acting on the block
Block has normal force, weight, friction and the force from the rod acting on itResultant force = 5*1.5=7.5horizontal component of force from rod = 207.5= 20 - FF= 12.5
