(x+4)((x^2) - kx - 5) is expanded and simplified. The coefficient of the x^2 term twice the coefficient of the x term. Work out the value of k.

(x + 4) (x2 - kx - 5) = x3 - kx2 - 5x + 4x2 - 4kx - 20 = x3 + (4-k)x2 + (-5-4k)x - 20.The coefficients are: (4-k) of x2 and (-5-4k) of x. Now we can write the equation:(4-k) = 2(-5 - 4k) /expand4 - k = -10 - 8k /+8k4 + 7k = -10 /-47k = -14 /divide by 7k = -2

MF
Answered by Márk F. Further Mathematics tutor

9902 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Point A lies on the curve y=3x^2+5x+2. The x-coordinate of A is 2. Find the equation of the tangent to the curve at the point A


How would I solve the following equation d^2x/dt^2 + 5dx/dt + 6x = 0


Given that xy=2 and y=3x+5, find x and y. Do not use trial and improvement.


Express (7+ √5)/(3+√5) in the form a + b √5, where a and b are integers.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning