A kettle has a 55% energy efficiency. The input energy for the kettle is 378,000 J per boil. Calculate the amount of energy dissipated in 5 boils.

Energy used for one boil = (3.78 x 105 / 100) x 55Energy used for one boil = 2.079 x 105 J Energy lost per boil = 3.78 x 105 -2.079 x 105Energy lost per boil = 1.701 x 105Energy lost per 5 boils = (1.701 x 105) x 5Energy lost per 5 boils = 8.51 x 105 J, 3 s.f. (or 851 kJ)

Answered by Ryan A. Physics tutor

3095 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

How do fossil fuel powered power stations and solar powered power stations generates electricity?


What is thermionic emission?


How to find wave speed from frequency and wave length.


What was the Rutherford gold foil experiment


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences