A kettle has a 55% energy efficiency. The input energy for the kettle is 378,000 J per boil. Calculate the amount of energy dissipated in 5 boils.

Energy used for one boil = (3.78 x 105 / 100) x 55Energy used for one boil = 2.079 x 105 J Energy lost per boil = 3.78 x 105 -2.079 x 105Energy lost per boil = 1.701 x 105Energy lost per 5 boils = (1.701 x 105) x 5Energy lost per 5 boils = 8.51 x 105 J, 3 s.f. (or 851 kJ)

Answered by Ryan A. Physics tutor

3032 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is the momentum of a 84 kg man running at 5 m/s?


What types of radiation are there?


What is radioactivity?


Sophia (mass 47Kg) is travelling to the right with a velocity of 7.2m/s and ​Neesha (mass 68Kg) is travelling to the left with a velocity 4.8m/s. When ​they meet, they hold hands and travel off together. Give their final ​velocity and direction


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences