Write equations for the reaction of propanoic acid with methanol and name any organic products.

This reaction is the formation of an ester because the reactants are a carboxylic acid and an alcohol.
Propanoic acid has 3 carbons and will have the functional group COOH:
CH3CH2COOH
Methanol has 1 carbon and an OH functional group:
CH3OH
So the equation is:
CH3CH2COOH + CH3OH ---> CH3CH2COOCH3 + H2O
The organic product is methyl propanoate because there are 3 carbons before the ester group and 1 carbon after the ester group.

Answered by Bethan H. Chemistry tutor

26870 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

What is a coordinate bond?


Calculate the concentration, in mol dm-3, of a solution of chloric (I) acid, HOCl , which has a pH of 4.23. Chloric acid is a weak acid, with Ka = 3.72 x 10^-8


Why are Amines more basic than Amides?


Write a balanced half equation for the oxidation of Mn 2+ to MnO4 -


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences