A team of four is chosen from six married couples. If a husband and wife cannot both be on the team, in how many ways can the team be formed?
There are 12 choices for the first memebr, then 10 for the next (as it cannot be the spouse), then 8, then 6.Therefore there are 121086 permutations where partners aren't together.However, this counts every order as different. For every combination there are 4! orders, so the final answer is121086/4! = 240.
LC
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