y = arcsec(x), Find dy/dx.

The key to this problem is to apply sec to both sides, and then differentiate implicitly: sec(y)=x; dsec(y)/dx = 1; tan(y)sec(y)dy/dx = 1; dy/dx = 1/(tan(y)sec(y)). Then using the fact that sec(y)=x and tan2x + 1 = sec2x, we can rewrite our derivative in terms of x only: dy/dx = 1/(x√(x2-1))

Answered by Nicholas Y. Maths tutor

3968 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the coordinates of the points where the lines y=x^2-5x+6 and y=x-4 intersect.


A curve C has equation: y = x^2 − 2x − 24x^1/2, x > 0; Find (i) dy/dx (ii) d^2y/dx^2


Two fair six sided dice, called A and B, are rolled and the results are added together. The sum of the dice is 8, what is the probability that two fours were rolled?


Find dy/dx when y = (3x-1)^10


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences