y = arcsec(x), Find dy/dx.
The key to this problem is to apply sec to both sides, and then differentiate implicitly: sec(y)=x; dsec(y)/dx = 1; tan(y)sec(y)dy/dx = 1; dy/dx = 1/(tan(y)sec(y)). Then using the fact that sec(y)=x and tan2x + 1 = sec2x, we can rewrite our derivative in terms of x only: dy/dx = 1/(x√(x2-1))
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