How do I expand a bracket to a negative power if it doesn't start with a 1.

Okay so consider (2 + x)^-1, we can only do the expansion we know if the bracket starts with a 1, to fix this we can factor a 2 out of the bracket so that it becomes (2(1 + x/2))^-1. Then by our rules of powers this is the same as 2^(-1)(1 + x/2)^(-1), 2^-1 = 1/2 and we can expand the remaining bracket as we have done before, so to get the first 3 terms we'd have:1/2(1 + (-1)(x/2) + (-1)(-2)(x/2)^2/2!)= 1/2(1 - x/2 + x^2/4)= 1/2 - x/4 + x^2/8

SM
Answered by Shaun M. Maths tutor

3998 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve has equation y^3+2xy+x^2-5=0. Find dy/dx.


A circle has eqn x^2 + y^2 + 2x - 6y - 40 = 0. Rewrite in the form (x-a)^2 + (y-b)^2 = d.


Derive from the standard quadratic equation, the form of the quadratic solution


Given that x = cot y, show that dy/dx = -1/(1+x^2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning