Find the integral of the following equation: y = cos^2(x)
First convert y into a suitably form.cos(2x) = 1 - 2cos2(x)cos2x = (1-cos(2x))/2
integral of y = integral of (1-cos(2x))/2 = (1/2)*(x-(1/2)sin(2x)) + C = x/2 - sin(2x)/4 + C
MH
First convert y into a suitably form.cos(2x) = 1 - 2cos2(x)cos2x = (1-cos(2x))/2
integral of y = integral of (1-cos(2x))/2 = (1/2)*(x-(1/2)sin(2x)) + C = x/2 - sin(2x)/4 + C
