Solve int(ln(x)dx)

To solve this we must use integration by parts: int(udv) = uv - int(vdu) (1) Hence let u = ln(x), dv = dx => du=(1/x)dx, v=x, and now using (1) and substituting values we obtain int(ln(x)dx) = ln(x)x - int(x(1/x)dx) = ln(x)x - int(dx) = xln(x) - x + C