Use integration to find the exact value of [integral of] (9-cos^2(4x)) dx

  1. you cannot integrate cos^2(4x) without making substitutions first. Use the cos^2(x) + sin^2(x) = 1 identity with the cos(2x)=cos^2(x)-sin^2(x), rearrange to get the identity cos(2x) = 2cos^2(x) - 1, then cos^2(x) = 0.5(cos(2x)+1)
    2) use this new identity to rewrite 6cos^2(4x), which will become 3cos(8x)+3
    3) integrate the constant 9 to become 9x
    4) integrate -(3cos(8x)+3) to get -(3/8sin(8x) - 3x)
    5) final answer is 6x - 3/8(sin(8x))
Answered by Anna F. Maths tutor

6785 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A circle has the equation x^2 + y^2 - 4x + 10y - 115 = 0. Express the equation in the form (x - a)^2 + (y - b)^2 = k, and find the centre and radius of the circle.


What is the area under the graph of (x^2)*sin(x) between 0 and pi


Differentiate y = 2x^3 + 6x^2 + 4x + 3 with respect to x.


Integrate y= x^3+3x^2-4x-7 between x values 1 and 3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences