y = 4sin(x)cos(3x) . Evaluate dy/dx at the point x = pi.

By product rule:u = 4sin(x) v = cos(3x)du/dx = 4cos(x) dv/dx = -3sin(3x)dy/dx = u (dv/dx) + v (du/dx)dy/dx = 4sin(x) * -3sin(3x) + cos(3x) * 4cos(x)dy/dx = -12sin(x)sin(3x) + 4cos(x)cos(3x)Evaluate at x = pi . dy/dx = 4.

Answered by Will F. Maths tutor

3906 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Use the chain rule to differentiate y=1/x^2-2x-1


How would I find the approximate area enclosed by the expression e^x*sin(x)*x^3 on an infinite scale?


The equation of a line is y=e(^2x)-9 and the line has points at (0,a) and (b,0). Find the values of a and b.


Express 3cos(theta) + 5sin(theta) in the form Rcos(theta - alpha) where R and alpha are constants, R>0 and 0<alpha<90. Give the exact value of R and the value of alpha to 2dp.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences