If photons of wavelength 0.1nm are incident on a 2m x 2m Solar Panel at a rate of 2.51x10^15s^-1, calculate the intensity, I, of the photons on the Solar Panel.

If wavelength = 0.1nm, we know (as E=hc/λ), the energy provided by each photon, E= 1.99x10¹⁵ J .Therefore, if they hit the panel at a rate of 2.51x10¹⁵s^-1, we know Power = Energy x Rate, =4.99WIntensity, I = Power / Area, = 4.99W/(2m x 2m)Therefore, I=1.25Wm^-2