If wavelength = 0.1nm, we know (as E=hc/λ), the energy provided by each photon, E= 1.99x1015 J .Therefore, if they hit the panel at a rate of 2.51x1015s-1, we know Power = Energy x Rate, =4.99WIntensity, I = Power / Area, = 4.99W/(2m x 2m)Therefore, I=1.25Wm-2