Using answer to previous question state the coordinates of the minimum
From previous question y=2(x+2)2-1Minimum would be when (x+2)2 is at it's smallest value, in this case when (x+2)=0 since any other value squared would be greater than 0. This occurs when x=-2, and y at this point would be y=-1 when put into the equation (2(0)-1=-1)Coordinates are (-2,-1)
MC
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