A particle A of mass 0.1kg is moving at a speed of 1.5m/s to the right. It collides with a particle B of mass 0.3kg moving at a speed of 1.1m/s to the right. Calculate change in momentum of particle A if particle B has a speed of 1.4m/s after collision.

Momentum is conserved during the collision.Momentum = mass x velocityMomentum before = momentum after(mv)P1 + (mv)Q1 = (mv)P2 + (mv)Q2(0.1 x 1.5) + (0.3 x 1.1) = 0.1vP2 + (0.3 x 1.4)vP2 = 0.6m/sChange in momentum of P:(mv)before = 0.1 x 1.5 = 0.15kgm/s(mv)after = 0.1 x 0.6 = 0.06kgm/sΔ(mv) = 0.15 – 0.06 = 0.09kgm/s

Answered by Juliet S. Maths tutor

2990 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you integrate the function cos^2(x)


Integrate, by parts, y=xln(x),


How do you rationalise the denominator?


A curve C is defined by the parametric equations x=(4-e^(2-6t))/4 , y=e^(3t)/(3t), t doesnt = 0. Find the exact value of dy/dx at the point on C where t=2/3 .


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences