Solve the simultaneous equations: 3x + y = -4 and 3x - 4y = 6

First subtract the first equation from the second getting:0 - 5y = 10-5y = 10Then divide both sides by (-5)y = -2Then substitute the y value of (-2) back into the first equation giving:3x + (-2) = -43x = -2x = -2/3And then check by substituting both values into the other equation that you were given.3(-2/3) -4(-2) = -2 +8=6There for the answer is, x=-2/3 and y=-2

LC
Answered by Luke C. Maths tutor

5432 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Given that x(a+bx)(a-bx)=25x-4x^3, what is the value of b^(-a)? a,b>0


Factorise 2x^3=10x+12x^2


Factorise x^2 - x - 6


Expand (2x+1)(x+4)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning