How to differentiate y=x^3+4x+1 when x=3

First of all you calculate dy/dx. To do this you look at each x individually. For the first x you multiply it by it's power and then minus 1 from the power to get 3x^2. Then multiply the next x by the power and minus 1 to get 4x. As 1 is the same as 1 multiplied by x^0, this means that you multiply 1 by 0 to get 0. Therefore dy/dx is 3x^2 + 4. Now substitute in x=3 to get dy/dx=31. This is the gradient.

Answered by Leana S. Maths tutor

2670 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

If f'(x)=3x(x - 1), find f(x)


Integrate ln(x/7) with respect to x


express 9^(3x+1) in the form 3^(ax+b)


Find dy/dx where y=e^(4xtanx)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences