2 Capacitors (c1 = 500mf) and (c2=300mf), are connected in parallel to a 10v d.c supply. Calculate the total capacitance of the circuit, and hence the total energy stored in the capacitors.

  1. Use the equation Ct = C1 + C2, 500mF + 300mF = 800mF or 800x10^-3F
    2) Appropriate equation is W=1/2 V^2 C
    W = (0.5)*(10^2)*800^-3 = 40J
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Answered by Samuel M. Physics tutor

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