Find the intersection coordinates of both axis with the function: f(x)=x^2-3x+4/3

Find the y1 coordinate, where x1 = 0, this is the intersection with y-axis. f(0)=4/3, therefore one intersection Py=[0,4/3]Find the x1,2 coordinates, where y = 0, this are the intersections with x-axis.0=x^2-3x+4/3, solve quadratic equation -> x1 =(3+(11/3)1/2)/2 -> Px1=[(3+(11/3)1/2)/2,0] -> x2 =(3-(11/3)1/2)/2 -> Px2=[(3-(11/3)1/2)/2,0]

MS
Answered by Martin S. Maths tutor

3061 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

If I had an equation with both 'x' and 'y' present, how would I find the gradient?


How can I remember trig identities?


Integrate the function (3x+4)^2 using methods of expansion and substitution


express x^2-4x+9 in the form (x-q)^2+y


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning