Find the intersection coordinates of both axis with the function: f(x)=x^2-3x+4/3
Find the y1 coordinate, where x1 = 0, this is the intersection with y-axis. f(0)=4/3, therefore one intersection Py=[0,4/3]Find the x1,2 coordinates, where y = 0, this are the intersections with x-axis.0=x^2-3x+4/3, solve quadratic equation -> x1 =(3+(11/3)1/2)/2 -> Px1=[(3+(11/3)1/2)/2,0] -> x2 =(3-(11/3)1/2)/2 -> Px2=[(3-(11/3)1/2)/2,0]
