Find the values of x given the equation (4x^2)-3x+1=2 using the quadratic formula.

4x2-3x+1=2The first step is to rearrange the equation, equating it to zero: 4x2-3x+1-2=0 which gives 4x2-3x-1=0. Next we apply the quadratic formula: x=(-b +/- sqrt(b2-4ac))/2a where a=4, b=-3 and c=-1. Substituting the values into the formula gives: x=(-(-3) +/- sqrt((-3)2-4(-4)))/2a. Simplifying gives: x=(3 +/- sqrt(25))/8. Solving this gives x=1 and x=-0.25.

Answered by Shahnaan M. Maths tutor

3066 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Calculate the area of a circle with a diameter of 20mm


Prove that 0.565656.... can be expressed as 56/99.


Find an expression for the nth term of this sequence: 3 - 11 - 19 - 27 - 35 . The nth term of a different sequence is 2n^3 + 3. Write down the first 3 terms of this sequence.


A family go into a shop, they buy three sandwiches and two packets of crisps. It costs them £9. Another family buy five sandwiches and six packets of crisps. It costs them £19. How much does two sandwiches and five packets of crisps cost?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences