Matt has 3 piles of coins, A , B and C. Altogether there was 72p. Pile B had twice as much as pile A. Pile C had three times as much as pile B. How much money was in Pile C?

so we know that A+B+C= 72. We also know that B=2A (1) and C=3B which means C=6A (2) and with this information we can re arrange to equation to be only have one variable. so A+2A+6A= 72 Collecting all the terms we get: 9A= 72so A=8subbing this into equation (1) and (2) we getB=16 and C=48
we can then check if our answer is correct by subbing the numbers into the original equation A+B+C= 728+16+48=72, which is correct.

Answered by Nazli D. Maths tutor

2882 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A family go into a shop, they buy three sandwiches and two packets of crisps. It costs them £9. Another family buy five sandwiches and six packets of crisps. It costs them £19. How much does two sandwiches and five packets of crisps cost?


Expand the brackets: (x-3)(x+4)


Solve the simultaneous equations. Equation one: 4x – 3y = 7. Equation two: 4x + y = -1.


solve: x^2= 4(x-3)^2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences