Matt has 3 piles of coins, A , B and C. Altogether there was 72p. Pile B had twice as much as pile A. Pile C had three times as much as pile B. How much money was in Pile C?

so we know that A+B+C= 72. We also know that B=2A (1) and C=3B which means C=6A (2) and with this information we can re arrange to equation to be only have one variable. so A+2A+6A= 72 Collecting all the terms we get: 9A= 72so A=8subbing this into equation (1) and (2) we getB=16 and C=48
we can then check if our answer is correct by subbing the numbers into the original equation A+B+C= 728+16+48=72, which is correct.

Answered by Nazli D. Maths tutor

2832 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Complete the square for x^2 + x - 6.


Solve the Simultaneous equations. 3x+5y=22 4x-5y=6


How do I expand single brackets?


Represent x = 0.0154 recurring as a fraction.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences