What mass of MgCl2 is formed in the following equation if 48g of Mg react in the following equation: Mg + 2HCI -> MgCI 2 + H

First you must calculate the moles of Mg that originally reacted. moles = mass/Mr moles=48/24 moles= 2 Molar ratio of Mg to MgCl2 is 1:1 Therefore 2 moles of MgCl2 were produced moles= mass/Mr mass= moles x Mr mass= 2 x (24+(2 x 35.5)) mass= 190g