I throw a ball straight up with an initial velocity of 2m/s. How high is it after a fifth of a second?

assign each variable to a value in s = ut + 1/2at2u = 2m/s t=0.2sa=-9.81m/s2so s = (2 x 0.2) + 1/2(-9.81)(0.2)2so s =

HA
Answered by Henry A. Physics tutor

2627 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is terminal velocity?


Explain the difference between energy and power.


Why do lasers produce an intense coherent beam of light?


State one property that all EM waves have in common.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning