I throw a ball straight up with an initial velocity of 2m/s. How high is it after a fifth of a second?

assign each variable to a value in s = ut + 1/2at2u = 2m/s t=0.2sa=-9.81m/s2so s = (2 x 0.2) + 1/2(-9.81)(0.2)2so s =

HA
Answered by Henry A. Physics tutor

2729 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is the difference between current and voltage?


What provides the centripetal force on a satellite and what are the factors that determine the size of the centripetal force on the satellite


What is terminal velocity and what causes it?


Why is the sky blue?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning