I throw a ball straight up with an initial velocity of 2m/s. How high is it after a fifth of a second?

assign each variable to a value in s = ut + 1/2at2u = 2m/s t=0.2sa=-9.81m/s2so s = (2 x 0.2) + 1/2(-9.81)(0.2)2so s =

HA
Answered by Henry A. Physics tutor

2687 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Why do astronauts feel weightless while in orbit?


Is momentum a vector or a scalar quantity?


What is the evidence for the Big Bang theory?


A car travelling at 14 m/s has to make an emergency stop so applies the brakes and it takes 1.5s to become stationary. What distance has the van travelled in that time?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning