what force does a person have to exert on one side of a seesaw if the other person weighs 70kg and is the same distance away from the pivot (2m) on the other side of the seesaw?

70kg x 9.8 = 686N x 2 = 1372 Nm, as 2m away again, divide by 2 = 868 Newtons

Answered by Marcus B. Physics tutor

1306 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

How does Ice make drinks Ice cold?


If a car has a mass of 670kg and has a driving force of 1200N and a force from resistance of 300N, what is the acceleration of the car? What is the speed of the car after 5 seconds?


Explain why the stability of a car can be improved by widening the wheel base and lowering the centre of gravity.


what is a half life of a substance and how can you work it out.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences