Solve: 2 sin(2x) = (1-sin(x))cos(x) for 0<x<2*Pi and give any values of x, if any, where the equation is not valid

Double angle formula:Sin(2x) = 2sin(x)*cos(x)==> 2sin(x)*cos(x) = (1-sin(x))*cos(x)       (2sin(x)-1+sin(x))*cos(x) = 0(3sin(x) - 1)*cos(x) = 0     i) cos(x) = 0,  ii) 3sin(x) = 1 ==> sin(x) = 1/3         i) x = Pi/2, 3Pi/2    ii) x = 0.3398 Rad,  2.8018 Rad

Answered by Henry F. Maths tutor

4458 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The equation of a circle is x^2+y^2-6x-4y+4=0. i) Find the radius and centre of the circle. ii) Find the coordinates of the points of intersection with the line y=x+2


How can I find all the solutions to cos(3x) = sqrt(2)/2 for 0<=x<=2pi ?


How to write an algebraic fraction in a given form e.g. (3+13x-6x^2)/(2x-3) as Ax + B + C/(2x-3) where A, B and C are natural numbers


Find the equation of the normal to the curve at the point (1, -1 ): 10yx^2 + 6x - 2y + 3 = x^3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences