Find all of the roots of unity, Zn, in the case that (Zn)^6=1

Here we use the complex exponential form of 1 which is e^(i 2n pi). Applying the sixth root and substituting in for integer values of n gives all roots in complex exponential form.These can be converted into a complex number of the form a +ib by using e^ix = cosx +isinx

CR
Answered by Callum R. Further Mathematics tutor

3235 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Are the integers a group under addition? How about multiplication?


Given y=arctan(3e^2x). Show dy/dx= 3/(5cosh(2x) + 4sinh(2x))


Find the general solution to f''(x)+ 3f'(x)+ 2f(x)=0


Given that the quadratic equation x^2 + 7x + 13 = 0 has roots a and b, find the value of a+b and ab.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning