Find all of the roots of unity, Zn, in the case that (Zn)^6=1

Here we use the complex exponential form of 1 which is e^(i 2n pi). Applying the sixth root and substituting in for integer values of n gives all roots in complex exponential form.These can be converted into a complex number of the form a +ib by using e^ix = cosx +isinx

CR
Answered by Callum R. Further Mathematics tutor

2917 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Let f(x)=x^x for x>0, then find f'(x) for all x>0.


The function f is defined for x > 0 by f (x) = x^1n x. Obtain an expression for f ′ (x).


Further Maths: How do you find the inverse of a 2 x 2 matrix?


What are imaginary numbers and why do we use them?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning