How would I solve a linear simultaneous equation?

When presented with a simultaneous equation, you need to find out the values of the letters (commonly x and y). You might be given two equations such as: a) 2x + 4y = 6, and b) -4x - 3y = 3. The first thing to do is to match up the x values in both equations, for example, you could times equation a) by 2, to get a new equation c) 4x + 8y = 12. Then you would plus or minus one equation from the other until the x value is eliminated, so here, you could add b) and c) to get 0x + 5y = 15. Then solve the remaining equation: 5y=15, so y=3 (dividing both sides by 5). Now that you have a y value, substitute it back into one of the original equations, such as a), to get: 2x + 4(3) = 6, which becomes: 2x + 12 = 6. Then rearrange until you have x on one side, making: 2x = -6. Then divide both sides by 2 to get x = -3. Therefore, the solution to these equations is: x = -3, and y = 3.

Answered by Ryan O. Maths tutor

2361 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations. x^2 + y^2 = 29. y-x = 3


Solve algebraically: 6a + b = 16 5a - 2b = 19


A house is bought for £150,000 at the start of 2005. For 3 years it loses 10% of its original value per year. After this time it loses 10% per year. What was its value at the end of 2011/start of 2012?


Line L goes through point (2,13) and is perpendicular to the line y = 4x-5. Find the equation of line L.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences