A curve has the equation y = 2x cos(3x) + (3x^2-4) sin(3x). Find the derivative in the form (mx^2 + n) cos(3x)

y = 2x cos(3x) + (3x2-4) sin(3x)
dy/dx = (2x x -sin(3x) x 3) + (2 x cos(3x)) + (6x sin(3x)) + ((3x2-4) cos(3x) x 3)
dy/dx = -6x sin(3x) + 2 cos (3x) + 6x sin(3x) + (9x2-12) cos(3x)
dy/dx = (9x2-12 + 2) cos (3x) = (9x2-10) cos (3x)
m = 9n = -10

Answered by Thomas L. Maths tutor

7985 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.


How should I aproach a connected rates of change question.


Find the exact solution of the equation in its simplest form: 3^x * e^4x = e^7.


Integrate x*sin(x) with respect to x.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences