Solve 8x + 9y = 3 and x + y = 0.

We have 8x + 9y = 3 [1] and x + y = 0 [2].We can make x or y the subject. Take y as subject we have y = -x [3].We substitute [3] into [1] and get 8x - 9x = 3 --> -x = 3 --> x = -3.Substituting x = -3 into [2] we get -3 + y = 0 --> y = 3.Final answer: x = -3 and y = 3.

Answered by Theresa O. Maths tutor

6529 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle.


Write x^2+4x-12 in the form (x+a)^2+b where 'a' and 'b' are constants to be determined.


X^2 - 4y = -8 y=3


Expand and simplify the following: (2x+3)(2x+5)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences