The equation of the line L1 is y = 3x – 2 . The equation of the line L2 is 3y – 9x + 5 = 0 Show that these two lines are parallel.

In order for two lines to be parallel, they need to have the same gradient (m). The gradient (m) is the coefficient of x in the line equation y=mx+c. Therefore, the gradient of L1 is 3 since 3 is the coefficient of x. For L2, you'll need to rearrange the equation so that you get it in the form of y=mx+c. So the first step would be to move -9x+5 to the right hand side: 3y=9x-5. Next, you'll have to divide everything by the coefficient of y (3). Therefore, you'll get y=3x-5/3. Now the gradient of L2 is 3 because x's coefficient is 3 and this is the same for L1 so the lines are parallel.

Answered by Asimina K. Maths tutor

2909 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Write 2x^2 + 6x + 6 in the form a(x^2 + b) + c by completing the square.


Solve the following equation: x^2- x - 12 = 0


Lisa, Max and Punita share £240 in the ratio 3 : 4 : 8 How much more money than Lisa does Punita get?


A ball, dropped vertically, falls d metres in t seconds. d is proportional to the square of t. The ball drops 45 metres in the first 3 seconds. How far does the ball drop in the next 7 seconds?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences