Find the value of x which satisfies the following equation 3x^2 +6x+3 = 0
Factorise the equation: (3x+3)(x+1) = 0. Anything multiplied by 0 is equal to 0 therefore (x+1)=0 and (3x+3) = 0. Solve for x: if x+1 =0 you need to subtract 1 from x to work out what x is (do the opposite of the sum) therefore x = -1Now do the same to the other equation: 3x +3 = 0. Subtract 3 and then divide by 3. x = -1. Therefore the final value of x is -1.
AS
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