The curve C has equation 16*y^3 + 9*x^2*y - 54*x = 0 a)Find dy/dx in terms of x and y

16y3 + 9x2y - 54x= 0 
a) Differentiate the terms separately dy/dx(16y3 + 9x2y - 54x) = dy/dx(16y3) + dy/dx(9x2y) - dy/dx(54x) = 48y2(dy/dx) + 18xy + 9x2(dy/dx) - 54 Implicit differentiation, treating y as a function of xdy/dx = (54 - 18xy)/(48y2+ 9x2) Factor out dy/dx and then cross multiply





JG
Answered by Joseph G. Maths tutor

4658 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Two particles, A and B, are moving directly towards each other on a straight line with speeds of 6 m/s and 8 m/s respectively. The mass of A is 3 kg, and the mass of B is 2 kg. They collide to form a single particle of speed "v" m/s. Find v.


How do I plot a graph of y=x^3-9x?


How do you complete the square?


The curve C has the parametric equations x=4t+3 and y+ 4t +8 +5/(2t). Find the value of dy/dx at the point on curve C where t=2.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning