Find dy/dx when y = (3x-1)^10

  1. First the power will be taken into account: multiply by 10 and take one away from the power:
    y = 10(3x-1)^9
    2) Then we will differentiate what is in the brackets and multiply it by step 1:
    y = (3x-1)dy/dx = 3
    10(3x-1)^9 multiplied by 3
    Therefore the answer is:
    30(3x-1)^9
SR

Related Maths A Level answers

All answers ▸

Use the substitution u=cos(2x)to find ∫(cos(2x))^2 (sin(2x))^3dx


(C3) Show that 4csc^2(x) - cot^2(x) = k can be expressed as sec^2(x) = (k-1)/(k-4) where k != 4


Find the equation of the normal to the curve y = 2x^2 -3x +7 at the point x = 1.


When using the addition rule in probability, why must we subtract the "intersection" to find the "union" with the Addition Rule?