Write x^2+4x-12 in the form (x+a)^2+b where 'a' and 'b' are constants to be determined.

This question is asking us to complete the square. To find the value of a we must halve the coefficient of x. So, in this question: a = 4/2 = 2. To find the value of b we take the constant at the end of the quadratic, -12, in this case and subtract a2 from it: x2+4x-12 = (x+2)2-12-(2)2 - our value of a = 2, and 22 = 4 so: (x+2)2-12-4 = (x+2)2-16. So, a = 2, and b = -16. To check if these 2 quadratics are equal we can simply expand (x+2)2-16 to get: x2+2x+2x+4-16 = x2+4x-12 so we know we have completed the square correctly.

Answered by Fizza A. Maths tutor

6838 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the quadratic 3x^2+11x+6=0


I need help understanding simultaneous equations with more than two variables, can you please help?


Expand and simplify the following equation: 6(x-3) - 4(x-5) = 0


Show that the following 2 lines are parallel: l1: 3y=15x+17 l2: 7y+5=35x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences