How many times further away from the pivot point of a seesaw does someone of double the weight have to sit in order for the it to balance?

Sum of moments in equilibrium must equal 0. The sum of clockwise moments must equal the sum of anticlockwise moments. W1 is the force exerted on the seesaw by the heavy person at distance D1 from the pivot and W2 is the force exerted by the lighter person at distance D2 from the pivot. Moment = perpendicular distance * forceW1 = 2 * W2Therefore, in order for the system to be in equilibrium, W1D1 = W2D2. Rewritten as 2W2D1 = W2D2.W2 cancels out and we are left with the ratio of distances from the people to the pivot point, D1/D2 = 1/2

Answered by River M. Physics tutor

2450 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Why do airbags make a car safer


Why do objects reach terminal velocity?


What is terminal velocity and what causes it?


Describe how a crumple zone on a car reduces injury to the driver in a crash.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences