How do you factorise a quadratic equation into the form (x+A)(x+B), for example x²+x-6 =0?

Quadratic equations are always given in the form ax2 +bx +c. One way of solving (finding values of x) and therefore factorising is to use the quadratic formula which is :x = −b ± √(b2 − 4ac)/ 2a ,using the values of a, b and c from the quadratic equation given. In the example given a=1 b=1 and c=-6 so when put in the formula: x = −1 + √(12 − 4(1x-6)) /2(1) = 2 or x = −1 -√(12 − 4(1x-6()/ 2(1) = -3 So here we have solved the equation but not factorised it. We know that x = 2 and x=-3. We also know that the equation = 0. Therefore when the equation is factorised into brackets the values within the brackets must =0. So if x=2, for the bracket to = 0 the value of A must be -2, and if x=-3 the value of B must be +3. Therefore x²+x-6 = (x-2)(x+3)

Answered by India J. Maths tutor

2403 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand and simplify the following equation: 6(x-3) - 4(x-5) = 0


The y-intercept of A is 7. A also passes through point (7, 2). (a) Find an equation of A in the form y = mx + c. (b) B is perpendicular to A and also has a y-intercept of 7. Write down the equation for B in the form y = mx + c.


make x the subject of 5(x-3) = y(4-3x)


Mixed rugby team of 20, 5 are female. 15 play at a time. i.) What is the percentage chance of a female playing. ii.)A minimum of three females must now be on the pitch. What is the percentage chance of 4 females playing?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences