Solve the simultaneous equations. x^2 + 2y=9, y-x=3

Use the method of substitution to answer this question.
Step 1: Rearrange one of the equations to find x or y.
y-x=3 y=x+3
Step 2: Substitute your y into the first equation
x2+2y=9 x2+2(x+3)=9
Step 3: Expand the brackets and rearrange to form a quadratic equation
x2+2x+6=9 x2+2x-3=0
Step 4: Factorise the equation to find your values for x
(x+3)(x-1)=0Therefore x=-3 or x=1
Step 5: Find the corresponding y values
y=x+3when x=-3 y=0 and when x=1 y=4

Answered by Kieran W. Maths tutor

3648 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

20% of 14,000


Solve x^(2) + 7x + 6 = 0.


Here are the first four terms of a quadratic sequence: 11 26 45 68. Work out an expression for the nth term.


Solve the simultaneous equations 5x + 2y = 4 and x - y - 5 =0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences