Make "a" the subject of the following equation: 2b = (3a+4)/(c-a)
In order to solve this question, we need to have all the terms containing 'a' on one side of the equals sign, and the other terms on the other side of the equals sign. First, we multiply both sides by (c-a), giving us:2b(c-a) = 3a+4,next we expand the left hand side:2bc-2ab = 3a+4,We now subtract 4 from both sides, and add 2ac:2bc-4 = 3a+2ab, next, we factorise the right hand side, and divide by whats in the brackets:(2bc-4)/(2b+3) = a,as required.
TD
Related Maths GCSE answers
All answers ▸What is the sum of 3/5 and 7/8?
The circle c has equation x^2+ y^2 = 1. The line l has gradient 3 and intercepts the y axis at the point (0, 1). c and l intersect at two points. Find the co-ordinates of these points.
A rectangle has sides of length 4x cm and (x+3)cm and has an area less than 112 cm^2, find the set of values x can take
how do you find intersections between two graphical functions?