Solve the following simultaneous equations: A. 2x-2y=18 and B. 3x+y=23

Step 1: Rearrange one equation to make y the subject. In equation B, we can move the 3x to the other side, making it negative and making the equation y=23-3xStep 2: Substitute our new value for y into equation A: 2x-2(23-3x)=18Step 3: Find the value of x by solving equation A: 2x-46+6x=18, 8x-46=18, 8x=64, x=8Step 4: Substitute our value for x into equation B to find the value of y: 3(8)+y=23, 24+y=23, y=-1Step 5: Substitute both values into equation A to confirm that these are correct: 2(8)-2(-1) = 16+2 = 18

Answered by Sahil M. Maths tutor

3230 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you know whether to use sin, cos or tan to find the angle in a triangle?


How do I remember the area of a circle if it's not in the formula book?


Write 4x^2+18x+2 in form a(x+m)+n.


Work out 64^2/3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences