Express '2x^2 + 8x + 30' in the form 'a(x+b)^2 + c'

b = B/2A = 8/(2x2) =8/4 = 2
c = C-((B^2)/4A) = 30-((8^2)/(4x2)) = 30-64/8 = 30-8 = 22
=> 2x^2 + 8x + 30 = 2(x+2)^2 + 22

CC
Answered by Charles C. Maths tutor

4452 Views

See similar Maths Scottish Highers tutors

Related Maths Scottish Highers answers

All answers ▸

show y=3x-5 is tangent to x^2 + y^2 +2x -4y - 5 = 0 and the point where they touch


A circle has equation x^2+y^2+6x+10y-7=0. Find the equation of the tangent line through the point on the circle (-8,-1).


Differentiate the equation: 3x^2 + 4x + 3


Solve log_2(3x + 7) = 3 + log_2(x – 1), x > 1.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning