Differentiate the following... f(x)= 5x^4 +16x^2+ 4x + 5
The rule for differentiating a simple equation such as this is, to times the coefficient by the power and the take one away from the power. Therefore, lets look at 5x^4 you would times the 5 by 4 to get 20x^4 and then you would take away one from the power so that it would be 20x^3. Follow this rule for 16x^2 to get 32x and then the 4x, when differentiated would just equal 4. The 5 would disappear when differentiating because you are differentiating the equation in terms of x and there is no x attached to the 5. So, the final answer would be f'(x)= 20x^3 + 32x +4
CM
Related Maths A Level answers
All answers ▸Express 1/(1+2x)(1-x) in partial fractions
∫(1 + 3√x + 5x)dx
A projectile is thrown from the ground at 30 degrees from the horizontal direction with an initial speed of 20m/s. What is the horizontal distance travelled before it hits the ground? Take the acceleration due to gravity as 9.8m/s^2
Two forces P and Q act on a particle. The force P has magnitude 7 N and acts due north. The resultant of P and Q is a force of magnitude 10 N acting in a direction with bearing 120°. Find the magnitude of Q and the bearing of Q.