Find values of x in the interval 0<x<360 degrees. For which 5sin^2(x) + 5 sin(x) +4 cos^2(x)=0

This question is split up into two parts.
Firstly recall the trigonometric identities you know, the trick here is to eliminate one of the squared terms. Using 4sin^2(x) +4cos^2(x) = 4, the cos term is eliminated.
Rearranging this equation leaves you with a strange quadratic equation, but if you pretend sin is x it actually looks quite simple and can be solved like a simple quadratic. Solve like this and replace x for sin and the solution follows

Answered by James G. Maths tutor

8361 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that 2log2(x+15) -log2(x) = 6, show that x^2-34x+225=0


How do I differentiate a pair of parametric equations?


Lorem ipsum dolor sit amet


Let f(x) and g(x) be two odd functions defined for all real values of x. Given that s(x)=f(x)+g(x), prove that s(x) is also an odd function.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences