Find values of x in the interval 0<x<360 degrees. For which 5sin^2(x) + 5 sin(x) +4 cos^2(x)=0

This question is split up into two parts.
Firstly recall the trigonometric identities you know, the trick here is to eliminate one of the squared terms. Using 4sin^2(x) +4cos^2(x) = 4, the cos term is eliminated.
Rearranging this equation leaves you with a strange quadratic equation, but if you pretend sin is x it actually looks quite simple and can be solved like a simple quadratic. Solve like this and replace x for sin and the solution follows

Answered by James G. Maths tutor

8364 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How would you show that a vector is normal to a plane in 3D space?


A curve has the equation: x^3 - x - y^3 - 20 = 0. Find dy/dx in terms of x and y.


What is an integral?


Find dy/dx of 5x^2 + 2y^3 +8 =17.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences