At what temperature does the reaction become feasible? When ΔH = 492.7 kJmol^-1 and ΔS = 542.6 JK^-1mol^-1.

When a reaction is feasible ΔG = 0. Rearrange the equation ΔG = ΔH - TΔS. So that when ΔG = 0,       T = ΔH / ΔS.

Must convert ΔS from JK^-1mol^-1 to kJK^-1mol^-1 by dividing it by 1000.

Then plug in numbers given so T = (492.7 kJmol^-1) / (0.5426 kJK^-1mol^-1) 

T = 908 K.

Answered by Lily W. Chemistry tutor

18793 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

How do I do redox calculations?


Predict the relative boiling points of propanal, butane and prop-2-en-1-ol from the highest to the lowest boiling point


What is the difference between London dispersion forces and hydrogen bonds?


Explain the trend in first ionisation energy along period 3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences