At what temperature does the reaction become feasible? When ΔH = 492.7 kJmol^-1 and ΔS = 542.6 JK^-1mol^-1.

When a reaction is feasible ΔG = 0. Rearrange the equation ΔG = ΔH - TΔS. So that when ΔG = 0,       T = ΔH / ΔS.

Must convert ΔS from JK^-1mol^-1 to kJK^-1mol^-1 by dividing it by 1000.

Then plug in numbers given so T = (492.7 kJmol^-1) / (0.5426 kJK^-1mol^-1) 

T = 908 K.

Answered by Lily W. Chemistry tutor

18760 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

Describe the arrangement of protons, neutrons and electrons in an atom of Neon (Atomic No. 10, Atomic Weight 20.18). You may use diagrams to aid you.


Name the reagent and explain the process of 1-bromoethane into propanoic acid


24.3cm^3 of 0.02moldm-3 KMnO4 reacted with 20cm^3 of iron (II) solution. Calculate the molarity of the iron (II) solution.


pH and Kw question: A student dissolves 1.75g of a drain cleaner (based on NaOH) in water and makes the solution up to 100cm3. The student measures the solution pH as 13.60. Determine the percentage of NaOH in the drain cleaner, in terms of mass (g).


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences