Make 'a' the subject of the formula: p = (3a + 5) / (4 - a)

Firstly, multiply the whole equation by (4 - a) to cancel out the denominator, so the equation becomes: p(4 - a) = (3a + 5). Then expand the brackets: 4p - ap = 3a +5. Then rearrange the equation to: 4p - 5 = 3a + ap, so you can factorise 'a' into brackets: 4p - 5 = a(3 + p). Now make 'a' the subject by dividing (4p - 5) by (3 + p), so your equation becomes: a = (4p - 5) / (3 + p).

Answered by Grace R. Maths tutor

4653 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve sequences and how can I get the nth number?


How to determine the number of unique real roots of a quadratic equation.


a) A line passes through (0,9) and (3,12) write down the equation of this line . b) A line perpendicular to the line in part a passes through the point (3,14) write the equation of this line.)


Prove algebraically that the straight line with equation x - 2y = 10 is a tangent to the circle with equation x^2 + y^2= 20


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences