What are the roots of (2x-5)(x-3) = 0

First off, roots means solve for x. 0 multiplied by any number equals 0, therefore, either one of the brackets must itself equal 0.We can solve this by firstly setting 2x-5 = 0, and solving for x. (+ 5) to both sides and (/ 2) to both sides, leaving x = 5/2Next, we set x-3 = 0.(+ 3) to both sides, leaving x = 3

AG
Answered by Ankit G. Maths tutor

4817 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that one interior angle of a a regular octagon = 135 degrees


Solve 2x-5=3x+4


Solve simultaneously: 3x+2y=7 & x-2y=-3


3n + 2 < 14, and 6n / (n ^2 + 5) >1. Find the values that n can take.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences