Express 4x/(x^2-9)-2/(x+3) as a single fraction in its simplest form

4x/(x2-9)-2/(x+3) = 4x/((x+3)(x-3))-2/(x+3) = 4x/((x+3)(x-3))-2(x-3)/((x+3)(x-3)) = (4x-2(x-3))/((x+3)(x-3)) = (2x+6)/((x+3)(x-3) = (2(x+3))/((x+3)(x-3)) = 2/(x-3)

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Answered by Charles S. Maths tutor

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