Express 4x/(x^2-9)-2/(x+3) as a single fraction in its simplest form

4x/(x2-9)-2/(x+3) = 4x/((x+3)(x-3))-2/(x+3) = 4x/((x+3)(x-3))-2(x-3)/((x+3)(x-3)) = (4x-2(x-3))/((x+3)(x-3)) = (2x+6)/((x+3)(x-3) = (2(x+3))/((x+3)(x-3)) = 2/(x-3)

CS
Answered by Charles S. Maths tutor

8476 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Explain the Chain Rule


4^x - 2^x+1 - 15 = 0


Binomially expand the equation (2+kx)^-3


Prove that 2Sec(x)Cot(x) is identical to 2Cosec(x)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning