Solve the following equation 2x^2+6x=8

2x^2+6x-8=0fx^2+3x-4=0(x-1)(x+4)=0x=-4 or x=1

HR

Related Maths GCSE answers

All answers ▸

The first three terms of a sequence are a, b, c. The term-to-term rule of the sequence is 'Multiply by 2 and subtract 4'. Show that c = 4(a – 3).


Simplify (2sin45 - tan45) / 4tan60


Solve x^2+5x+6=0 by factorising


solve the simultaneous equations , 5a+2b=23 & 9a-2b=19, algebraically.